32. Second Fundamental Theorem of Calculus
Dated: 30-10-2024
Dummy Variable
If we change the letter
for the variable
of integration
1 but don't change the limits
, then values of definite integrals
2 remains the same
\[\int_{1}^{2}x^{2}dx=\frac{x^{3}}{3}\bigg]_{1}^{2}=\frac{26}{3}\]
\[\int_{1}^{2}f(t)dt=\frac{t^{3}}{3}\bigg]_{1}^{2}=\frac{26}{3}\]
\[\int_{1}^{2}f(y)dy=\frac{y^{3}}{3}\bigg]_{1}^{2}=\frac{26}{3}\]
Definite integral
2 With Variable Upper Limit
If we have an integral
1 of the form
\[\int^x_a\]
Then we have to use different letter for the variable
of integration
1 to differentiate it from the upper limit
. Such as
\[\int_{2}^{x}t^{2}dt\]
The Theorem
\[A(x)=\int_{a}^{x}f(t)dt\]
\[\frac{d}{dx}(A(x))=A'(x)=\frac{d}{dx}\left(\int_{a}^{x}f(t)dt\right)=f(x)\]
If the integrand
1 is continuous
,3 then the derivative
4 of a definite integral
2 with respect to its upper limit
is equal to the integrand
1 evaluated at the upper limit
.
\[\frac{d}{dx}\left(\int_{a}^{x}f(t)dt\right)=f(x)\]
References
Read more about notations and symbols.
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Read more about definite integrals. ↩↩↩
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Read more about continuity. ↩
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Read more about derivatives. ↩